Continuous Random Variable MCQs with Solution - 3


Note: Correct Option is Marked (*)

101. The time it takes a technician to fix a computer is exponentially distributed with a mean of 10 minutes.  What is the variance of the amount of time it takes a technician to fix a computer?
a. 0.01
b. 0.1
*c. 100
d. 10
e. 20

102. The time it takes a technician to fix a computer is exponentially distributed with a mean of 10 minutes.  What is the standard deviation of the amount of time it takes a technician to fix a computer?
a. 0.01
b. 0.1
c. 100
*d. 10
e. 20

103. The time it takes a technician to fix a computer is exponentially distributed with a mean of 20 minutes.  What is the standard deviation of the amount of time it takes a technician to fix a computer?
a. 0.05
b. 15
c. 100
d. 10
*e. 20

104. Flaws occur in telephone cabling at an average rate of 4.4 flaws per 1km of cable.  What is the expected distance between flaws (in km)?
a. 4.4
b. 3.2
*c. 0.227
d. 0.313
e. 2.2

105. Flaws occur in telephone cabling at an average rate of 3.2 flaws per 1km of cable.  What is the expected distance between flaws (in km)?
a. 4.4
b. 3.2
c. 0.227
*d. 0.313
e. 2.2

106. Flaws occur in telephone cabling at an average rate of 4.4 flaws per 1km of cable.  What is the variance of the distance between flaws?
*a. 0.052
b. 0.098
c. 19.36
d. 10.24
e. 2.2

107. Flaws occur in telephone cabling at an average rate of 3.2 flaws per 1km of cable.  What is the variance of the distance between flaws?
a. 0.052
*b. 0.098
c. 19.36
d. 10.24
e. 2.2

108. Cars arrive at a tollgate at an average rate of 10 cars per hour.  What is the mean time between arrivals (in minutes)?
*a. 6 minutes
b. 0.1 minutes
c. 3 minutes
d. 0.05 minutes
e. 4 minutes

109. Cars arrive at a tollgate at an average rate of 20 cars per hour.  What is the mean time between arrivals (in minutes)?
a. 6 minutes
b. 0.1 minutes
*c. 3 minutes
d. 0.05 minutes
e. 4 minutes

110. Cars arrive at a tollgate at an average rate of 15 cars per hour.  What is the mean time between arrivals (in minutes)?
a. 6 minutes
b. 0.1 minutes
c. 3 minutes
d. 0.05 minutes
*e. 4 minutes

111. The convenor of a first-year statistics programme at a certain university receives, on average, 5 emails per 30 minutes.  What is the mean time between the arrival of emails in her inbox (in minutes)?
a. 30 minutes
b. 0.167 minutes
*c. 6 minutes
d. 0.5 minutes
e. 5 minutes

112. The convenor of a first-year statistics programme at a certain university receives, on average, 5 emails per 30 minutes.  What is the variance of the time between the arrival of emails in her inbox?
a. 36 minutes
*b. 36 minutes2
c. 6 minutes
d. 6 minutes2
e. 0.028 minutes2

113. Calls are received by the switchboard of a large company at an average rate of 10 calls every 15 minutes.  What is the mean time between calls (in minutes)?
a. 2 minutes
b. 0.67 minutes
c. 15 minutes
d. 10 minutes
*e. 1.5 minutes

114. You and I own a company called Deliveries Inc. We have a large fleet of delivery trucks. On average we have 10 breakdowns per 5 day working week. What is the expected time (in days) between breakdowns?
a. 1 day
*b. 0.5 day
c. 2 days
d. 0.75 day
e. 5 days

115. You own a very old car which breaks down, on average, 3 times a year.  What is the mean time between break downs, in months, of your car?
a. 3 months
b. 0.25 months
c. 12 months
*d. 4 months
e. 0.5 months

116. You own a very old car which breaks down, on average, 3 times a year.  What is the standard deviation of the time between break downs, in months, of your car?
a. 3 months
b. 0.25 months
c. 12 months
*d. 4 months
e. 0.5 months

117. The diameters of oranges found in the orchard of an orange farm follow a normal distribution with a mean of 120mm and a standard deviation of 10mm.  What proportion of oranges in the orchard have a diameter between 110mm and 130mm?
*a. 0.6826
b. 0.8186
c. 0.3829
d. 0.4332
e. 0.2858

118. The diameters of oranges found in the orchard of an orange farm follow a normal distribution with a mean of 120mm and a standard deviation of 10mm.  What proportion of oranges in the orchard have a diameter between 110mm and 140mm?
a. 0.6826
*b. 0.8186
c. 0.3829
d. 0.4332
e. 0.2858

119. The diameters of oranges found in the orchard of an orange farm follow a normal distribution with a mean of 120mm and a standard deviation of 10mm.  What proportion of oranges in the orchard have a diameter between 115mm and 125mm?
a. 0.6826
b. 0.8186
*c. 0.3829
d. 0.4332
e. 0.2858

120. The diameters of oranges found in the orchard of an orange farm follow a normal distribution with a mean of 120mm and a standard deviation of 10mm.  What proportion of oranges in the orchard have a diameter between 105mm and 120mm?
a. 0.6826
b. 0.8186
c. 0.3829
*d. 0.4332
e. 0.2858

121. The diameters of oranges found in the orchard of an orange farm follow a normal distribution with a mean of 120mm and a standard deviation of 10mm.  What proportion of oranges in the orchard have a diameter between 100mm and 115mm?
a. 0.6826
b. 0.8186
c. 0.3829
d. 0.4332
*e. 0.2858

122. The random variable X is normally distributed with a mean of 70 and a standard deviation of 10.  What is the probability that X is within one standard deviation of the mean?
*a. 0.683
b. 0.954
c. 0.271
d. 0.340
e. 0.161

123. The random variable X is normally distributed with a mean of 70 and a standard deviation of 10.  What is the probability that X is between 50 and 90?
a. 0.683
*b. 0.954
c. 0.271
d. 0.340
e. 0.161

124. The random variable X is normally distributed with a mean of 70 and a standard deviation of 10.  What is the probability that X is between 65 and 72?
a. 0.683
b. 0.954
*c. 0.271
d. 0.340
e. 0.161

125. The random variable X is normally distributed with a mean of 70 and a standard deviation of 10.  What is the probability that X is between 72 and 84?
a. 0.683
b. 0.954
c. 0.271
*d. 0.340
e. 0.161

126. The random variable X is normally distributed with a mean of 70 and a standard deviation of 10.  What is the probability that X is between 50 and 61?
a. 0.683
b. 0.954
c. 0.271
d. 0.340
*e. 0.161

127. The starting annual salaries of newly qualified chartered accountants (CA’s) in South Africa follow a normal distribution with a mean of R180,000 and a standard deviation of R10,000.  What is the probability that a randomly selected newly qualified CA will earn between R160,000 and R190,000 per annum?
*a. 0.819
b. 0.242
c. 0.286
d. 0.533
e. 0.307

128. The starting annual salaries of newly qualified chartered accountants (CA’s) in South Africa follow a normal distribution with a mean of R180,000 and a standard deviation of R10,000.  What is the probability that a randomly selected newly qualified CA will earn between R165,000 and R175,000 per annum?
a. 0.819
*b. 0.242
c. 0.286
d. 0.533
e. 0.307

129. The starting annual salaries of newly qualified chartered accountants (CA’s) in South Africa follow a normal distribution with a mean of R180,000 and a standard deviation of R10,000.  What is the probability that a randomly selected newly qualified CA will earn between R185,000 and R200,000 per annum?
a. 0.819
b. 0.242
*c. 0.286
d. 0.533
e. 0.307

130. The starting annual salaries of newly qualified chartered accountants (CA’s) in South Africa follow a normal distribution with a mean of R180,000 and a standard deviation of R10,000.  What is the probability that a randomly selected newly qualified CA will earn between R170,000 and R185,000 per annum?
a. 0.819
b. 0.242
c. 0.286
*d. 0.533
e. 0.307

131. The starting annual salaries of newly qualified chartered accountants (CA’s) in South Africa follow a normal distribution with a mean of R180,000 and a standard deviation of R10,000.  What is the probability that a randomly selected newly qualified CA will earn between R150,000 and R175,000 per annum?
a. 0.819
b. 0.242
c. 0.286
d. 0.533
*e. 0.307

132. Given that X is Normally distributed with a mean of 80 and a variance of 100, what is p(85 < X < 90)?
*a. 0.150
b. 0.341
c. 0.286
d. 0.625
e. 0.533

133. Given that X is Normally distributed with a mean of 80 and a variance of 100, what is p(70 < X < 80)?
a. 0.150
*b. 0.341
c. 0.286
d. 0.625
e. 0.533

134. Given that X is Normally distributed with a mean of 80 and a variance of 100, what is p(60 < X < 75)?
a. 0.150
b. 0.341
*c. 0.286
d. 0.625
e. 0.533

135. Given that X is Normally distributed with a mean of 80 and a variance of 100, what is p(75 < X < 95)?
a. 0.150
b. 0.341
c. 0.286
*d. 0.625
e. 0.533

136. Given that X is Normally distributed with a mean of 80 and a variance of 100, what is p(70 < X < 85)?
a. 0.150
b. 0.341
c. 0.286
d. 0.625
*e. 0.533

137. In a large statistics class the heights of the students are normally distributed with a mean of 172cm and a variance of 25cm2.  What proportion of students are between 162cm and 182cm in height?
*a. 0.954
b. 0.601
c. 0.718
d. 0.883
e. 0.270

138. In a large statistics class the heights of the students are normally distributed with a mean of 172cm and a variance of 25cm2.  What proportion of students are between 170cm and 180cm in height?
a. 0.954
*b. 0.601
c. 0.718
d. 0.883
e. 0.270

139. In a large statistics class the heights of the students are normally distributed with a mean of 172cm and a variance of 25cm2.  What proportion of students are between 160cm and 175cm in height?
a. 0.954
b. 0.601
*c. 0.718
d. 0.883
e. 0.270

140. In a large statistics class the heights of the students are normally distributed with a mean of 172cm and a variance of 25cm2.  What proportion of students are between 165cm and 181cm in height?
a. 0.954
b. 0.601
c. 0.718
*d. 0.883
e. 0.270

141. In a large statistics class the heights of the students are normally distributed with a mean of 172cm and a variance of 25cm2.  What proportion of students are between 175cm and 185cm in height?
a. 0.954
b. 0.601
c. 0.718
d. 0.883
*e. 0.270

142. A statistical analysis of long-distance telephone calls indicates that the length of these calls is normally distributed with a mean of 240 seconds and a standard deviation of 40 seconds.  What proportion of calls last less than 180 seconds or more than 300 seconds?
a. 0.911
b. 0.034
*c. 0.134
d. 0.067
e. 0.548

143. A bakery finds that the average weight of its most popular package of cookies is 32.06g with a standard deviation of 0.10g.  Assuming that the weight of the package of cookies follows a normal distribution, what portion of cookie packages will weigh less than 31.90 g or more than 32.30 g?
*a. 0.06
b. 0.24
c. 0.78
d. 0.01
e. 0.00

144. A statistical analysis of long-distance telephone calls indicates that the length of these calls is normally distributed with a mean of 240 seconds and a standard deviation of 40 seconds.  What proportion of calls lasts less than 180 seconds?
a. 0.214
b. 0.094
c. 0933
d. 0.466
*e. 0.067

145. In a large statistics class the heights of the students are normally distributed with a mean of 172cm and a variance of 25cm2.  What is the probability that a randomly selected student from this class will be taller than 180cm?
*a. 0.055
b. 0.655
c. 0.274
d. 0.919
e. 0.992

146. In a large statistics class the heights of the students are normally distributed with a mean of 172cm and a variance of 25cm2.  What is the probability that a randomly selected student from this class will be taller than 170cm?
a. 0.055
*b. 0.655
c. 0.274
d. 0.919
e. 0.992

147. In a large statistics class the heights of the students are normally distributed with a mean of 172cm and a variance of 25cm2.  What is the probability that a randomly selected student from this class will be taller than 175cm?
a. 0.055
b. 0.655
*c. 0.274
d. 0.919
e. 0.992

148. In a large statistics class the heights of the students are normally distributed with a mean of 172cm and a variance of 25cm2.  What is the probability that a randomly selected student from this class will be taller than 165cm?
a. 0.055
b. 0.655
c. 0.274
*d. 0.919
e. 0.992

149. In a large statistics class the heights of the students are normally distributed with a mean of 172cm and a variance of 25cm2.  What is the probability that a randomly selected student from this class will be taller than 160cm?
a. 0.055
b. 0.655
c. 0.274
d. 0.919
*e. 0.992

150. Using the standard normal table, the sum of the probabilities to the right of z = 2.18 and to the left of z = -1.75 is:
a. 0.4854
b. 0.4599
c. 0.0146
d. 0.0401

*e. 0.0547

Comments